If 4^x+3^x=5^x, then the value of X=?
If 4^x+3^x=5^x, then the value of X=? 🍁 To solve for x in the equation 4^x + 3^x = 5^x, we can use logarithms. Taking the logarithm of both sides of the equation with base 10, we get: xlog10(4) + xlog10(3) = x*log10(5) Dividing both sides by x, we get: log10(4) + log10(3) = log10(5) Using a calculator or logarithm tables, we can find that: log10(4) ≈ 0.60206 log10(3) ≈ 0.47712 log10(5) ≈ 0.69897 Substituting these values into the equation, we get: 0.60206 + 0.47712 ≈ 1.07918 ≈ 0.69897 Therefore, x ≈ 1.07918. Is the method of solving correct? This is not correct. Because You can't take the logarithm of numbers added separately. Cross check 4² + 3² = 25 = 5² ➖ 1. Using logarithmic identity method: If 4^x+3^x=5^x, then the value of X=?........ The equation 4^x + 3^x = 5^x can be solved by taking the natural logarithm of both sides. We have: ln(4^x + 3^x) = ln(5^x) Using the logarithmic identity ln(a^b) = b*ln(a), we can simplify the left-hand side: xln(4) + xln(3) = x*ln...
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